Find the sum of the natural numbers less than 100 which are divisible by 7.
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Look total divisible number less than 100 are
100/7 = 14
which are 7 + 14 + 21 + 28 +..... + 98
So take 7 as Common then solve it
7(1+2+3+4+5+...+14) Till 14 because less than 100 is 98 and this is 7x14 which is last under 100
now total of Natural Numbers = n(n+1)/2
So [14 × (14+1)] / 2
14×15 / 2
So 105
Now 7(105) = 735
If you have any doubt comment please. If my answer helped you in any way then please mark my answer as Brainliest Answer.
100/7 = 14
which are 7 + 14 + 21 + 28 +..... + 98
So take 7 as Common then solve it
7(1+2+3+4+5+...+14) Till 14 because less than 100 is 98 and this is 7x14 which is last under 100
now total of Natural Numbers = n(n+1)/2
So [14 × (14+1)] / 2
14×15 / 2
So 105
Now 7(105) = 735
If you have any doubt comment please. If my answer helped you in any way then please mark my answer as Brainliest Answer.
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