Find the sum of the number in between 1 and 1000 which are divisible by 9 options a) 55944 b) 54954 c) 99994 d) 99894
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Answer:
a) 55944
Step-by-step explanation:
The series is
9,18,27,36...999
so first we have to find how many terms
an=a+(n-1)d
999=9+(n-1)9
999=9n
n=111
Sn=n/2×(2a+(n-1)d)
where
n=no.of terms
a=first term
d=common difference
=111/2[2×9+(111-1)×9]
=111/2[18+990]
=111×1008/2
=111×504
=55944
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