Question

find the sum of the numbers between 1 to 140 which are divisible by 6​

Answer 1

Answer:

Clearly, the numbers from 1 to 140 which are divisible by 4 are 4,8,12,...140.

This is an AP with first term a=4, common difference d=4 and last term l=140.

Let there be n terms in this AP.

Then,

a

n

=140⇒a+(n−1)d

140=4+(n−1)×4

∴n=35

∴ required sum =S

n

=

2

n

[a+l]=

2

35

[4+140]

=2520

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