find the sum of the numbers between 1 to 145 which are divisible by 5
Answers
Answer:
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Step-by-step explanation:
This type of questions solved by using AP
First and last term which is divisible by 4 in given series is 4 and 144 respectively
Then the new series is…
4 ,8,12,……, 144
Then we find total number of term in new series using formula…
Tn=a+(n-1)d
Tn:- nth term of given series
a:- first term of given series
n:- total number of term of given series
d:-common difference of given series
Tn =144,a=4,d=4
Put these values in above formula
144=4+(n-1)4
n=36
Then use formula of summation of AP…
S=n/2(a+l)
S:-sum of given series
n:-total no of term
a:-first term of given series
l:-last term of given series
n=36,a=4,l=144
Put these values in above formula…
S=36/2(4+144)
S=2664
Therefore sum of all the natural number between 1 to 145 which is divisible by 4 is 2664