find the sum of the numbers between 100 and 300 that are divisible by 3 or 7
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Numbers between 100 to 300 that are divisible by 7 are
105, 112, 119, 126….. 294
This is arithmetic progression where common difference is 7, 1st term is 105, last term = 294
Total no. of terms = {(last term - 1st term)/ common difference } + 1
={ (294–105)/7 } + 1
= 27 + 1 = 28 terms
Sum of AP = n(1st term + last term)/2
n is number of terms
Sum = 28(105+294)/2
= 14(399)
= 14*(400–1)
= 5600 - 14 = 5586 (Ans)
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