Find the sum of the odd numbers between 0 and 50
15. A contract on construction job specifies a penalty for delay of completion beyond a
certain date as follows: 200 for the first day, 250 for the second day, 300 for the third
day, etc., the penalty for each succeeding day being 50 more than for the preceding day.
How much money the contractor has to pay as penalty, if he has delayed the work by 30
days?
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a + ( n - 1) d = an
=> 1 + ( n - 1) 2 = 49
=> ( n - 1) 2 = 48
=> ( n - 1) = 24
=> n = 25.
So,
Sn = n/2 × ( a +l)
= 25 /2× ( 1 +49)
= 25 /2 × 50
= 25 ×25
= 62
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