Find the sum of the odd numbers between 10 and 50
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We need to find the sum of odd numbers between 10 and 50.
The odd numbers from 10 to 50 go like 11, 13, 15......49
Thus forming an AP 11, 13, 15....49 (Where a=11, d=2, last term (an)= 49)
We know that an = a + (n-1) d
Putting values in the formula,
49= 11 + (n-1) 2
49= 11 + 2n - 2
49= 9 + 2n
2n= 40
n= 40/2
n= 20
So now, substitute all the values in the formula Sn= n/2 (a + an)
Sn= 20/2 ( 11 + 49)
= 10 ( 60)
= 600
Answer= 600
The odd numbers from 10 to 50 go like 11, 13, 15......49
Thus forming an AP 11, 13, 15....49 (Where a=11, d=2, last term (an)= 49)
We know that an = a + (n-1) d
Putting values in the formula,
49= 11 + (n-1) 2
49= 11 + 2n - 2
49= 9 + 2n
2n= 40
n= 40/2
n= 20
So now, substitute all the values in the formula Sn= n/2 (a + an)
Sn= 20/2 ( 11 + 49)
= 10 ( 60)
= 600
Answer= 600
Answered by
2
see it's an arthematic progression known as A.P. with common difference 2
first term (a)=11
end term(l) =49
total number of terms (n)=25-5=20
so sum =n/2(a+l)
sum=20/2(11+49)
=600
first term (a)=11
end term(l) =49
total number of terms (n)=25-5=20
so sum =n/2(a+l)
sum=20/2(11+49)
=600
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