Find the sum of the of the length bases of a trapezium whose altitude is 11 cm and whose area is 0.55 cm
mritunjaykumarpcd9h9:
area 0.55 cm² correct your question
Answers
Answered by
6
Area of trapezium = 1/2 x(l + b) x h
0.55=1/2 x (l + b) x 11
(l+ b)=0.55x2 / 11
= 0.5 x 2
= 1.0 cm Ans
0.55=1/2 x (l + b) x 11
(l+ b)=0.55x2 / 11
= 0.5 x 2
= 1.0 cm Ans
Answered by
5
Area of trapezium is 1/2 (a+b) h
therefore
0.55 =1/2(a+b) 11
0.55*2=(a+b)*11
1.1/11 a+b
0.1 = a+b
therefore
0.55 =1/2(a+b) 11
0.55*2=(a+b)*11
1.1/11 a+b
0.1 = a+b
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