Math, asked by naagulikha5178, 11 months ago

Find the sum of the place value of all the digits of 6215

Answers

Answered by knjroopa
1

Answer:

93,324

Step-by-step explanation:

Given  

Find the sum of the place value of all the digits of 6215

ANSWER

To find the place value of all digits we need to find sum of all numbers at first, second, third and fourth place.

The number of four digits formed using 6215 is 4 x 3 x 2 x 1 = 24

So 24/4 = 6

In 24 numbers formed, each digit of 6215 will be 6 times at 1st, 2nd, 3rd and 4th place.

So consider thousand’s place. Sum of numbers at first place that is thousand’s place will be

6(6 + 2 + 1 + 5) = 6 x 14 = 84

Sum of numbers in hundred’s place will be

6(6 + 2 + 1 + 5) = 6 x 14 = 84

Sum of numbers in ten’s place will be

6(6 + 2 + 1 + 5) = 6 x 14 = 84

Sum of numbers in unit’s place will be

6(6 + 2 + 1 + 5) = 6 x 14 = 84

So sum of all four digit numbers formed using 6215 will be

      84 x 1000 = 84,000

      84 x 100 =      8,400

      84 x 10   =         840

       84 x 1 =              84

     Total is 93,324

So the sum of the place value of all the digits of 6215 is 93,324

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