Find the sum of the product of zeores of p(x) =2(x^2 -3)+x
Answers
Answered by
0
Step-by-step explanation:
p(x)=2x^2+x-6
sum of the roots=-1/2
product of the roots=6/2=3
the roots of the equation are -2,3/2
Answered by
0
p(x) = 2x² - 6 + x
We know that, if the roots are a and b
a+b = -b/a and
ab = c/a
then,
a+b = -1/2
ab = -6/2 = -3
Hope this is helpful to you
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