Find the sum of the products (a + 2b)
(2a - b) and (3a + b) (3b-2a).
Answers
Answered by
19
Answer:
Step-by-step explanation:
(a+2b)(2a-b) = a(2a-b) + 2b(2a-b)
= 2a²-ab+ 4ab-2b²
= 2a²-2b²+3ab
(3a+b)(3b-2a)= 3a(3b-2a)+b(3b-2a)
= 9ab-6a²+3b²-2ab
= -6a²+3b²+7ab
sum = 2a²-2b²+3ab+(-6a²+3b²+7ab)
= 2a²-2b²+3ab-6a²+3b²+7ab
= 2a²-6a²-2b²+3b²+3ab+7ab
= -4a²+1b²+10ab
Answered by
7
Answer:
it's very easy sum
Step-by-step explanation:
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