Question

Find the sum of the products of the corresponding terms of the sequence 2,4,8,16,32 and128,32,8,2,1/2.

Answer 1

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Answer 2

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Here's your Answer...

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FIRST SERIES IS 2,4,8,16,32

SECOND SERIES IS 128,32,8,2,1/2

PRODUCT OF THIS SERIES 256,128,64,32,16

a = 256 

r = 1/2

Sn = a(1 - r^n) / 1 - r

        =256{1 - (1/2)^n}/1 - (1/2)

         =256{1 - (1/2)^5}1/2

         =512{1 - 1/32}

        = 512{31/32} 

       =     496 

THEREFORE THE SUM OF THE PRODUCT OF 2 SERIES GIVEN IS 496
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