Math, asked by rehanfaisalashoka, 1 day ago

Find the sum of the reciprocal of the root of the equation 2 − 9 − 20 = 0​

Answers

Answered by PharohX
1

Answer:

Correct Questions.

 \sf \: 2 {x}^{2}  - 9x - 20 = 0

here

a= 2, b=-9 , c= -20

 \sf \:  \frac{1 }{ \alpha }  +  \frac{1}{ \beta }  \\

 \sf \:  =  \frac{ \alpha  +  \beta }{ \alpha  \beta }  \\

 \sf \: Sum \:  of \:  roots = (  \alpha  + \beta ) =   - \frac{b}{a}  =   - \frac{ - 9}{2}  \\

 \sf \: Sum \:  of \:  roots =\frac{ 9}{2}  \\

 \sf \: Product  \: of  \: roots =  \alpha  \beta  =  \frac{c}{a}  =  -  \frac{20}{2}   =  - 10\\

 \sf \:  =  \frac{ \alpha  +  \beta }{ \alpha  \beta }  =  \frac{9}{2}  \div( -10)   =  -\frac{9}{20} \\

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