Question

find the sum of the remaining zeros
x^3-3x^2-4x+12=0

Answer 1

☺☺ HERE IS YOUR ANSWER ☺☺

x^3- 3x^2-4x+12=0
x^2(x-3) -4(x-3)=0
(x^2-4)(x-3)=0
(x^2-2^2) (x-3)=0
(x-2)(x+2)(x-3)=0
x=2 or x=(-2) or x=3

sum of all zeros = 2 + (-2) + 3
=2-2+3
=3

Answer 2

HEYA MATE!!

IDENTITY USED ==>

FOR CUBIC POLYNOMIAL,

SUM OF ZEROS ==> -b/a

SO,
SUM OF ALL THE ZEROS ==>-(-3)/1==>3

#KEVIN

HOPE IT HELPS YOU ☺☺☺

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