Question

Find the sum of the roots of x^2 + 4x - 12 = 0

Answer 1

Answer:

-4

Step-by-step explanation:

${x }^{2} + 4x - 12 = 0 \\ \\ {x}^{2} - 2x + 6x - 12 = 0 \\ \\ x(x - 2) + 6(x - 2) = 0 \\ \\ (x - 2)(x + 6) = 0 \\ \\ x = 2 \: and \: ( - 6) \\ 2 + ( - 6) \\ - 4$

Answer 2

Answer:

Step-by-step explanation:-4

Step-by-step explanation: