find the sum of the Rost 1000
Postile integens.
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Answer:(i) Let S = 1 + 2 + 3 + . . . + 1000
Using the formula Sn =n/2(a+1)
for the sum of the first n terms of an AP,
we have S1000
=1000/2(1+1000)
=500x1001
=500500
So, the sum of the first 1000 positive integers is 500500.
Step-by-step explanation:
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