find the sum of the series (1+1/2^2)+(1/2+1/2^4)+(1/2^2+1/2^6)_ _ _ to infinity
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Answer:
numbers are in g.p.
formula:a/1-r
a=1+1/2^2, r=1/2
1+1/2^2/1-1/2=1+1/2^2*2=2+2/2^2=2+1/2=5/2
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