Question

Find the sum of the series 1+2+3+...+60

Answer 1

Answer:

Here's your answer

$an = a + (n - 1)d \\ 60 = 1 + (n - 1)1 \\ \\ 59 = 1n - 1 \\ \\ 60 = n$

$sum = \frac{n}{2} (a + an) \\ \\ = \frac{60}{2} (1 + 60) \\ \\ = 30 \times 61 \\ \\ = 1830$

Hope it helps ✌

Answer 2

Answer:

Step-by-step explanation:

by using the formula

sₐ=n/2(a₁+a₂)

where,

n= number of terms

wkt

n=a₂-a₁/d-1

n=60-1/1-1

n=58 terms

now,

sₐ=58/2(1+60)

sₐ=29*61

sₐ=1769