Question

find the sum of the series 1+2+4+8......12 terms

Answer 1

1+2+4+8+16+32 64+128+256+512+1042+2084+4168
=7317

Answer 2

Answer:4095

Step-by-step explanation:

The given series is in geometric progression..

So,

Sn=a(r^n-1/r-1)

a=1;

r=2/1=2

n=12;

S12=1(2^12-1/2-1)

     =4096-1/1

     =4095

∴the sum of the given series is 4095...