Question

Find the sum of the series 1+3.5+6+8.5+...+101.
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+- 629,2349x
TIF 1913 – 17​

Answer 1

Answer:

Hi everyone hru guy's

Step-by-step explanation:

Sn = (n/2)(a1 + an)

a1 = 1

But we need first to determine n.

To do that we need d:

d = 3.5-1 = 6-3.5 = 8.5-6 = 2.5

an = a1 + (n - 1)∙d

101 = a1 + (n - 1)∙2.5

Solve that and get n = 41

Sn = (n/2)(a1 + an)

S41 = (41/2)(1 + a41)

S41 = (41/2)(1 + 101)

S41 = (41/2)(102)

S41 = 2091

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Answer 2

Answer:

Sn = (n/2)(a1 + an)

a1 = 1

But we need first to determine n.

To do that we need d:

d = 3.5-1 = 6-3.5 = 8.5-6 = 2.5

an = a1 + (n - 1)∙d

101 = a1 + (n - 1)∙2.5

Solve that and get n = 41

Sn = (n/2)(a1 + an)

S41 = (41/2)(1 + a41)

S41 = (41/2)(1 + 101)

S41 = (41/2)(102)

S41 = 2091

Step-by-step explanation:

hope it is helpful to you........