find the sum of the series 101 + 99 + 97 + ...... + 47
Answers
Answered by
8
_____ hey mate ____
here is your answer
101+99+97+..+47
this is an arithmetic series, the nth term is found by
Xn = 101 -(2 * (n-1))
*****************************************************
we need to determine how many terms to sum
47 = 101 -(2*(n-1))
47 = 101 -2n +2
2n = 56
n = 28
there are 28 terms to sum
*****************************************************
sum = (28/2)*(101+47)
sum = 14 * 148
sum = 2072
hope the answer and method will help u!!!!
here is your answer
101+99+97+..+47
this is an arithmetic series, the nth term is found by
Xn = 101 -(2 * (n-1))
*****************************************************
we need to determine how many terms to sum
47 = 101 -(2*(n-1))
47 = 101 -2n +2
2n = 56
n = 28
there are 28 terms to sum
*****************************************************
sum = (28/2)*(101+47)
sum = 14 * 148
sum = 2072
hope the answer and method will help u!!!!
Answered by
9
Hey dear here is your answer!!!!
First to find no. of terms ....
An = a + (n-1)d
47=101+(n-1)-2
-54=(n-1)-2
n-1=27
n=28
To find sum :-
Sn= n/2 (a+l)
Sn = 14(101+47)
Sn =2072
Hope it helps !!!
First to find no. of terms ....
An = a + (n-1)d
47=101+(n-1)-2
-54=(n-1)-2
n-1=27
n=28
To find sum :-
Sn= n/2 (a+l)
Sn = 14(101+47)
Sn =2072
Hope it helps !!!
manojkalita362pbes33:
thanks
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