Question

Find the sum of the series: 128, 64, 32, 16, 8, upto infinity. Geeks for geeks

Answer 1

Answer:

hope this answer in the above attachment helps you}:‑)

Answer 2

The sum of the infinity term of GP, $S_{\infty}$ = 256

Step-by-step explanation:

The given sequence are:

128, 64, 32, 16, 8, ..... up to ∞ are in GP.

Here, first term (a) = 128, common ratio (r) = $\dfrac{64}{128}$ = $\dfrac{1}{2}$

To find, the sum of the series = ?

We know that,

The sum of the infinity term of GP, $S_{\infty}$

$=\dfrac{a}{1-r}$

= $\dfrac{128}{1-\dfrac{1}{2}}$

= $\dfrac{128}{\dfrac{2-1}{2}}$

= 128 × 2 = 256

∴ The sum of the infinity term of GP, $S_{\infty}$ = 256