Question

find the sum of the series 2+3+5+6+8+9+.........+(3n-1)+(3n).​

Answer 1

Answer:

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Step-by-step explanation:

In the Series 2+3+5+6+8+9....

there are two series

1st) 2 + 5 + 8 ......3n-1

2nd ) 3 + 6 + 9.....3n

Sum of 1st series = [n(2 + 3n-1) ]/ 2

Sum of 2nd series = [n(3 + 3n)]/2

Total sum = n(3n+2)