Find the sum of the series 2+4+6+⋯ upto first 40 terms.
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Answer:
2+4+6+12+10+14+16+18+20+22+24+26+28+30+32+34+36+38+40=412
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Answer:
the given series is in Form of AP
first term, a=2
common difference, d=2
no of term, n=40
so sum=n/2[2a+(n-1)d]
=40/2[2×2+(40-1)2]
=20[4+39×2]
=20×[4+78]
=20×82=1640
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