find the sum of the series: 2+7+12+...........297.
Answers
Answered by
34
Hey here is your answer
=========================
![s = \frac{n}{2} (a + l) s = \frac{n}{2} (a + l)](https://tex.z-dn.net/?f=s+%3D+%5Cfrac%7Bn%7D%7B2%7D+%28a+%2B+l%29)
here,
a = 2
l = 297
d = 5
n = ?
T![= (a + (n - 1)d) = (a + (n - 1)d)](https://tex.z-dn.net/?f=+%3D+%28a+%2B+%28n+-+1%29d%29)
![297 = 2 + (n - 1)5 \\ 297 - 2 = (n - 1)5 \\ \frac{295}{5} = (n - 1) \\ 59 + 1 = n \\ n = 60 297 = 2 + (n - 1)5 \\ 297 - 2 = (n - 1)5 \\ \frac{295}{5} = (n - 1) \\ 59 + 1 = n \\ n = 60](https://tex.z-dn.net/?f=297+%3D+2+%2B+%28n+-+1%295+%5C%5C+297+-+2+%3D+%28n+-+1%295+%5C%5C+%5Cfrac%7B295%7D%7B5%7D+%3D+%28n+-+1%29+%5C%5C+59+%2B+1+%3D+n+%5C%5C+n+%3D+60)
now , sum of given ap
![s = \frac{60}{2} (2 + 297) \\ \: \: \: = 30 \times 299 \\ \: \: \: =8970 s = \frac{60}{2} (2 + 297) \\ \: \: \: = 30 \times 299 \\ \: \: \: =8970](https://tex.z-dn.net/?f=s+%3D+%5Cfrac%7B60%7D%7B2%7D+%282+%2B+297%29+%5C%5C+%5C%3A+%5C%3A+%5C%3A+%3D+30+%5Ctimes+299+%5C%5C+%5C%3A+%5C%3A+%5C%3A+%3D8970+)
==============================
Hope it may helpful to you
plzz mark me as brqinlist
=========================
here,
a = 2
l = 297
d = 5
n = ?
T
now , sum of given ap
==============================
Hope it may helpful to you
plzz mark me as brqinlist
Anonymous:
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Answered by
1
Step-by-step explanation:
(2x−3y+5z)(4x
2
+9y
2
+25z
2
+6xy+15z−10xz)
=(2x−3y+5z)[(2x)
2
+(3y)
2
+(5z)
2
−(2x)(−3y)−(−3y)(5z)−(2x)(5z)]
Using formula (x+y+z)(x
2
+y
2
+z
2
−xy−yz−zx)=x
3
+y
3
+z
3
−3xyz
=(2x)
3
+(−3y)
3
+(5z)
3
−3.2x.(−3y).5z
=(2x)
3
+(−3y)
3
+(5z)
3
+90xyz
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