find the sum of the series 5+8+11+........to 60 terms
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This series is Arithmetic Progression (AP).
For this AP,
First Term, a = 5
Common Difference, d = 8-5 = 3
No. of terms, n = 60
Sum of first n terms, Sn
Sn = n/2 (2a + (n-1)d )
∴S₆₀ = 60/2 (2(5) + (60 - 1)*3)
= 30 (10 + 59 * 3)
= 30 (10 + 177)
= 30 * 187
∴S₆₀ = 5610
Thus, sum of first 60 terms of the A.P. is 5610.
For this AP,
First Term, a = 5
Common Difference, d = 8-5 = 3
No. of terms, n = 60
Sum of first n terms, Sn
Sn = n/2 (2a + (n-1)d )
∴S₆₀ = 60/2 (2(5) + (60 - 1)*3)
= 30 (10 + 59 * 3)
= 30 (10 + 177)
= 30 * 187
∴S₆₀ = 5610
Thus, sum of first 60 terms of the A.P. is 5610.
QGP:
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Answered by
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a = 5
d = 8-5 = 3
n = 60
Sn = n/2 (2a + (n-1)d )
∴S₆₀ = 60/2 (2(5) + (60 - 1)*3)
= 30 (10 + 59 * 3)
= 30 (10 + 177)
= 30× 187
∴S₆₀ = 5610
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