Find the sum of the series
it is in gp
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common ratio is root of(3)
sum of 8 terms in series =a(r^n-1)/r-1
=1/√3(3^4-1)/(√3-1)
=1/√3(80)(√3+1)/2
=40(√3+1)/√3
sum of 8 terms in series =a(r^n-1)/r-1
=1/√3(3^4-1)/(√3-1)
=1/√3(80)(√3+1)/2
=40(√3+1)/√3
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