Find the sum of the series upto 10 terms 2,12,36,80,..?
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Given : 2 12 36 80
To Find : Sum of series upto 10 term
Solution:
2 12 36 80
2 = 1³ + 1²
12 = 2³ + 2²
36 = 3³ + 3²
80 = 4³ + 4²
Series is n³ + n²
∑( n³ + n²) = ∑ n³ + ∑ n²
∑ n³ = {(n)(n + 1)/2}²
∑ n² = n(n + 1)(2n + 1)/6
Sum of 10 term
∑( n³ + n²) = {(n)(n + 1)/2}² + n(n + 1)(2n + 1)/6
n = 10
= {(10)(10 + 1)/2}² + 10(10 + 1)(2(10) + 1)/6
= 55² + 10(11)(21)/6
= 3025 + 385
= 3410
3410 is sum of given series upto 10 terms
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