Find the sum of the smallest and the largest angles of a triangle if their angles are in the ratio 3:4:5
Arya4012:
3p+4p+5p=180° or,12p=180° or,p=(180/12) or,p=15°..........then the largest angle will be 75° & smallest will be 15°
45° smallest correct it
Answers
Answered by
1
Let the angels are 3p , 4p and 5p
Then ,
3p + 4p + 5p = 180°
12p = 180°
p = 15°
•°• The smallest angle ( 3p ) = 3 × 15° = 45°
•°• The largest angle ( 5p ) = 5 × 15° = 75°
Then ,
3p + 4p + 5p = 180°
12p = 180°
p = 15°
•°• The smallest angle ( 3p ) = 3 × 15° = 45°
•°• The largest angle ( 5p ) = 5 × 15° = 75°
multyply main wrong hain 5×15 =75 not 60
Answered by
1
Answer:
Step-by-step explanation:
Let the name of the triangle be ABC
Let the common multiple be x
Therefore angle A = 3x, angle B = 4x, angle C = 5x
We know that sum of measures of an angle of a triangle is 180°
Therefore angle A+angle B+angle C = 180°
3x + 4x + 5x = 180°
12x = 180°
x = 180/12
x = 15
Angle A = 3x = 45°
Angle C = 5x = 75°
Angle A and Angle C are the smallest and biggest angles
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