Question

Find the sum of the squares of first 10 natural numbers.​

Answer 1

Answer:

385

Step-by-step explanation:

The sum of squares of natural numbers

=

$\frac{n(n + 1)(2n + 1)}{6}$

here n is 10

Therefore,

$\frac{10(10 + 1)(2(10) + 1)}{6}$

$\frac{10(11)(21)}{6}$

$\frac{2310}{6}$

= 385

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