Find the sum of the terms 18pq, -15pq, 3pq.
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2
6pq is the answer of this question
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0
Answer:
Answer:
\begin{gathered}(2pq + 3 {q}^{2} )(3pq - {q}^{2} ) \\ = {q}^{2} (2p + 3q)(3p - q) \\ = {q}^{2} (6 {p}^{2} - 2pq + 9pq - 3 {q}^{2} ) \\ = {q}^{2} (6 {p}^{2} + 7pq - 3 {q}^{2} )\end{gathered}
(2pq+3q
2
)(3pq−q
2
)
=q
2
(2p+3q)(3p−q)
=q
2
(6p
2
−2pq+9pq−3q
2
)
=q
2
(6p
2
+7pq−3q
2
)
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