Question

find the sum of the terms of an a.p 2,6,10,14,......,32

Answer 1

A = 2, d = 6 - 2 = 4, n = 32 Sum of n terms = sn = n/2[2a+(n-1)d] Substituting = 32/2[2(2)+(32-1)4] = 16[4+(31)4] = 16[4+124] = 16 * 128 = 2048 Hence Sum of terms of AP 2,6,10,14..........,32. is 2048

Answer 2

a=2      d=6-2=4               l=32
Sn=n/2{a+l}