Question

find the sum of the terms of finite APs, here a=2, d=5/3-2=-1/3, then a+(n-1)(-1/3)=-6

Answer 1

Answer:

sum of n terms of AP = n/2(2a+(n-1)d)

using your given values we get,

Sn = n/2[(4+(n-1)(-1/3)]

Sn = n/2[4+1/3 -n/3]

Sn = n/2[7/3 -n/3]

Sn = 7n/6 - n²/6

Sn = n(7-n)/6 (Ans)

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