Question

Find the sum of the three consecutive multiples of 9 if the sum is 81.

give answer of this question please ​

Answer 1

Answer:

18,27,81

Step-by-step explanation:

Let the three consecutive multiples of 9 be k, k + 9 and k + 18. Given that, Their sum is 81. ∴ The Required Smaller number is: k ⇒ 18 .

Let the three consecutive multiples of 9 be

9(x-1),9(x),9(x+1)

sum=81

9(x-1+x+x+1)=81

9(3x)=81

27x=81

x=81/27

x=3

9(3-1),9(3),9(3+1)

9(2),9(3),9(4)

18,27,36

Answer 2

your answer is arriving.......|

knock.. .knock

let 1 number be x

2and number be x+9

3rd number be x+18

x+x+9+x+18 = 81

3x+27 = 81

3x = 81-27

3x=54

x = 18

x = 18

x + 9 = 18 + 9 = 27

x + 18 = 18 + 18 = 36

your answers are :

18

27

36