find the sum of the whole numbers from 30 to 140
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By using the formulas of arithmetic progression ,
we know that the first term will be 30, total number of terms will be 110 , and the common difference will be 1 , in this question
Now according to the formula : sum of terms in an Arithmetic progression is S=n/2 ( 2a + (n-1)d)
Where n is total number of terms , a is first term , and d is common difference ,
Now substitute the values ... S= 110/2 ( 2x30 + (110-1) 1)
This will be equal to 110/2 ( 169) =9295
Please mark this answer as brainiest answer if you understood it
we know that the first term will be 30, total number of terms will be 110 , and the common difference will be 1 , in this question
Now according to the formula : sum of terms in an Arithmetic progression is S=n/2 ( 2a + (n-1)d)
Where n is total number of terms , a is first term , and d is common difference ,
Now substitute the values ... S= 110/2 ( 2x30 + (110-1) 1)
This will be equal to 110/2 ( 169) =9295
Please mark this answer as brainiest answer if you understood it
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