Question

find the sum of the zeroes in x2 +3x + 2 ​

Answer 1

Step-by-step explanation:

Given the polynomial x

2

−3x−5

For solving we have to make it a zero,

∴x

2

−3x−5=0

Now, by formula,

x=

2⋅1

−(−3)±

(−3)

2

−4⋅1⋅(−5)

=

2

3±

9+20

=

2

3±

29

∴x=

2

3+

29

,

2

3−

29

∴ Sum of the roots, (S)=

2

3+

29

+

2

3−

29

=

2

3+

29

+3−

29

=

2

6

=3

and product of the roots, (P)=(

2

3+

29

)×(

2

3−

29

)

=

4

9−29

=

4

−20

=−5

Now, using S and P as zeros we have,

x=3

⇒x−3=0

and x=−5

⇒x+5=0

∴ the required polynomial is,

(x−3)(x+5)

=x

2

+2x−15.

Answer 2

Answer:

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