Question

Find the sum of the zeroes of p(x) = (x - 3) and q(x) = (2x - 8)?​

Answer 1

Step-by-step explanation:

p(X) =(x-3)

x-3=0

X=3( let it be alpha)

q(X)=(2x-8)

2x-8=0

X=8/2

X=4(let it be beta)

Alpha+beta =-b/a

3+4=-b/a

7/1=-b/a

Alpha×beta=c/a

3×4=c/a

12/1=c/a

Sum of zero=ax^2+bx+c

1×(3)^2-7(2)+12

9-14+12

9-2

7