Question

Find the sum of the zeroes of the cubic polynomial p(x)=5x3 + 8x2 + 3x + 1​

Answer 1

Answer:

$sum \: of \: zero = - \frac{8}{5}$

Step-by-step explanation:

$sum \: of \: zero = - \frac{8}{5}$

Answer 2

Step-by-step explanation:

Given:-

The cubic polynomial p(x)=5x^3 + 8x^2 + 3x + 1

On Comparing this with the standard cubic polynomial ax^3+bx^2+cx+d

We have

a = 5

b=8

c=3

d=1

Now we know that

Sum of the zeroes of a cubic Polynomial

= -(coefficient of x^2)/coefficient of x^3

=> Sum of the zeores= -8/5

Answer:-.

Sum of the zeores of the given cubic polynomial is -8/5

Used formulae:-

• the standard cubic polynomial ax^3+bx^2+cx+d

• Sum of the zeroes of a cubic Polynomial
• = -(coefficient of x^2)/coefficient of x^3