find the sum of the zeroes of the polynomial 6x^2+11x+5
Answers
Answered by
2
Answer:
6x²+11x+5
= 6x²+6x+5x+5
= 6x(x+1)+5(x+1)
= (x+1)(6x+5)
Zeroes: x+1 = 0
x = -1
6x+5 = 0
x = -5/6
Sum of the zeroes
= -1+(-5/6)
= -1-5/6
= -6-5/6
= -11/6
6x²+11x+5
= 6x²+6x+5x+5
= 6x(x+1)+5(x+1)
= (x+1)(6x+5)
Zeroes: x+1 = 0
x = -1
6x+5 = 0
x = -5/6
Sum of the zeroes
= -1+(-5/6)
= -1-5/6
= -6-5/6
= -11/6
Answered by
1
Answer:
hey mate
Step-by-step explanation:
SUM OF ZEROES=-b/a
sum of zeroes=-11/6
so
-11/6is correct ans
hope it will help u
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