Question

find the sum of the zeroes of the polynomial p^2-5p-24​

Answer 1

Answer:

I think the answer is p=5+root 71/2 and 5 - root 71/2

Answer 2

Answer:

5 is the sum of the zeroes of the polynomial.

Step-by-step explanation:

Explanation:

Given in the question, $p^2 -5p -24$

Polynomial -  A polynomial is an expression that solely uses the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables. It consists of indeterminates and coefficients.

Let $\alpha \ and \beta$ are the zeroes of the given polynomial.

Step 1:

We have $p^2 -5p -24$

coefficient of  $p^2$ = 1 and $coefficient of p$ = -5 and constant value = -24

As we know,

sum of zeroes of the polynomial ($\alpha + \beta$) = $\frac{-coefficient \ of p}{coefficient of p^2}$ = $\frac{-b}{a}$

Where a is the coefficient of $p^2$ and b is the coefficient of p.

So,from the polynomial  a = 1 and b = -5.

⇒$\alpha + \beta$ = $\frac{-(-5)}{1}$= 5

Final answer:

Hence, 5 is the sum of the zeroes of the given polynomial.

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