Question

find the sum of the zeroes of the quadratic polynomial x^2+ 7x+ 12
​

Answer 1

Answer:

x2 +3x+4x+12

x(x+3) +4(x+3)

(x+4)(x+3)

so zeroes -3 and -4

pls brainliest

Step-by-step explanation:

Answer 2

Step-by-step explanation:

let the two zeroes be'a'and'b'.

x^2+7x+12=0

x^2+3x+4x+12=0

x(x+3)+4(x+3)=0

(x+4)(x+3)=0

x+4=0 or x+3=0

x=(-4) or x=(-3)

a=(-4) and b=(-3)

Sum=a+b=(-4)+(-3)=(-7)