Question

Find the sum of the zeros and product of the zeros of the polynomial 6s2-3-7s​

Answer 1

Answer:

Sum of zeros = 7/6

Product of zeros = -1/2

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Answer 2

6x² −3−7x=6x

2

−7x−3=0

⇒6x

2

+2x−9x−3=0

⇒2x(3x+1)−3(3x+1)=0

⇒(2x−3)(3x+1)=0

Zeros = 2/3 , 3/−1

α+β= a/-b

⇒ 2/3 -3/1= 6/7 = 6/(-7)

= a/-b

αβ= a/c

⇒( 2/3 ) (3/-1)

= 2/-1

= 6/-3= a/c

Hence proved.