Question

find the sum of the zeros of the polynomial P of X is equals to 2 x square - 9 X + 10​

Answer 1

Answer:

9/2

Given:- p(x) = 2x² - 9x + 10

, we know that sum of zeros = -b/a

here, a = 2

b = -9

and c = 10

now, alpha + beeta = - (-9) / 2

= 9/2

hope, I'll help you to understand....

Answer 2

The sum of zeroes of given polynomial is $\dfrac{9}{2}$.

Step-by-step explanation:

We have a polynomial given as :

$p(x)=2x^2-9x+10$

If the polynomial is in the form of $ax^2+bx+c$, then the sum of zeroes of polynomial is equal to $\dfrac{-b}{a}$

We have, a = 2 and b = -9

So,

Sum of zeroes of polynomial is : $\dfrac{-b}{a}=\dfrac{-(-9)}{2}=\dfrac{9}{2}$

So, the sum of zeroes of given polynomial is $\dfrac{9}{2}$.

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