Question

find the sum of the zeros of the quadratic polunomial​

Answer 1

f(x) = x² - 9

For zeroes of the polynomial:

=> f(x) = 0

=> x² - 9 = 0

=> x² - (3)² = 0

=> (x+3) (x-3) = 0 { Using a²- b² = (a+b) (a-b) }

=> x = -3, 3

Sum of the zeroes = -3 + 3 = 0

OR

Sum of the zeroes = -b/a

since there is no coefficient (b) of x term, so the solution is 0

Answer 2

The sum of the zeros of the quadratic polynomial​ is zero.

To find : Sum of the zeros of the quadratic polynomial.

Given :

Quadratic polynomial : x² - 9 = 0

General form of quadratic equation is ax² + bx + c = 0.

Sum of the zero's can be calculated as, $-\frac{b}{a}$.

Product of the zero's can be calculated as, $\frac{c}{a}$.

Comparing "x² - 9 = 0" and "ax² + bx + c = 0"      

a = 1 ; b = 0 ; c = -9.

So, sum of the zero's = $-\frac{b}{a}$ = $- \frac{0}{1}$ = 0.

Product of the zero's = $\frac{c}{a}$ = $-\frac{9}{1}$ = -9.

x² - 9 = 0

Using identities, $(a^2 - b^2) = (a+b)(a-b)$

(x² - 3²) = (x + 3)(x -3) = 0

x = -3 ; x = 3  

Therefore, the sum of the zero is 0.

To learn more...

1. Find the sum and product of zeros of the quadratic polynomial 3x2-4x+7              

brainly.in/question/6220382

2. Find the sum of the zeros of the given quadratic polynomial -3x²+k​

brainly.in/question/8956805