find the sum of the zeros of the quadratic polunomial
Answers
f(x) = x² - 9
For zeroes of the polynomial:
=> f(x) = 0
=> x² - 9 = 0
=> x² - (3)² = 0
=> (x+3) (x-3) = 0 { Using a²- b² = (a+b) (a-b) }
=> x = -3, 3
Sum of the zeroes = -3 + 3 = 0
OR
Sum of the zeroes = -b/a
since there is no coefficient (b) of x term, so the solution is 0
The sum of the zeros of the quadratic polynomial is zero.
To find : Sum of the zeros of the quadratic polynomial.
Given :
Quadratic polynomial : x² - 9 = 0
General form of quadratic equation is ax² + bx + c = 0.
Sum of the zero's can be calculated as, .
Product of the zero's can be calculated as, .
Comparing "x² - 9 = 0" and "ax² + bx + c = 0"
a = 1 ; b = 0 ; c = -9.
So, sum of the zero's = = = 0.
Product of the zero's = = = -9.
x² - 9 = 0
Using identities,
(x² - 3²) = (x + 3)(x -3) = 0
x = -3 ; x = 3
Therefore, the sum of the zero is 0.
To learn more...
1. Find the sum and product of zeros of the quadratic polynomial 3x2-4x+7
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2. Find the sum of the zeros of the given quadratic polynomial -3x²+k
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