Find the sum of those integers from 1 and 500 which are multiple of 2 as well as 5
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Hello,
We first find the LCM of 2 and 5 which is 10.
Now all those integers which are multiples of 10 are also the multiples of 2 and 5.
Therefore, multiples of 2 as well as of 5 between 1 and 500 are:
10, 20, 30, ...., 490
Series forms an AP with first term,a=10 and common difference,d=20-10=10.
Let total number of terms of this AP be n.
Therefore, nth term of AP, an = Last term, l= 490
an=a(n-1)d=l;
10+(n-1)10=490;
(n-1)10=480;
n-1=48;
n=48+1=49;
n=49
Thus,sum of n terms of AP is given as:
S₄₉=49/2 (10+490);
=49/2 (500);
=49×250=12250
hope it helps you
if yes then please mark as brainliest
bye :-)
We first find the LCM of 2 and 5 which is 10.
Now all those integers which are multiples of 10 are also the multiples of 2 and 5.
Therefore, multiples of 2 as well as of 5 between 1 and 500 are:
10, 20, 30, ...., 490
Series forms an AP with first term,a=10 and common difference,d=20-10=10.
Let total number of terms of this AP be n.
Therefore, nth term of AP, an = Last term, l= 490
an=a(n-1)d=l;
10+(n-1)10=490;
(n-1)10=480;
n-1=48;
n=48+1=49;
n=49
Thus,sum of n terms of AP is given as:
S₄₉=49/2 (10+490);
=49/2 (500);
=49×250=12250
hope it helps you
if yes then please mark as brainliest
bye :-)
Answered by
0
Answer:
12750 is the answer.....
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