find the sum of thr first 100 natural numbers.
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Step-by-step explanation:
The formula to calculate the sum of ‘n’ natural numbers.
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100n = 100
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100n = 100Sn = 100/2 (1 + 100)
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100n = 100Sn = 100/2 (1 + 100)= 100/2 (101)
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100n = 100Sn = 100/2 (1 + 100)= 100/2 (101)= 50 × 101
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100n = 100Sn = 100/2 (1 + 100)= 100/2 (101)= 50 × 101= 5050.
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100n = 100Sn = 100/2 (1 + 100)= 100/2 (101)= 50 × 101= 5050.Sum of 1+2+3+4……100 is 5050.
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100n = 100Sn = 100/2 (1 + 100)= 100/2 (101)= 50 × 101= 5050.Sum of 1+2+3+4……100 is 5050.Answer
The formula to calculate the sum of ‘n’ natural numbers.S = n⁄2 (a + L)“S” is the sum of the arithmetic sequence,“a” as the first term,“d” the common difference between the terms,“n” is the total number of terms in the sequence and“L” is the last term of the sequence.Here a = 1l = 100n = 100Sn = 100/2 (1 + 100)= 100/2 (101)= 50 × 101= 5050.Sum of 1+2+3+4……100 is 5050.AnswerTherefore, the sum of first 100 natural numbers = 5050.
Answer:
Sum of first 100 natural number is 5050.