Question

Find the sum of three consecutive integers if the sum of the first two is equal to twenty four less than four times the third integer.

Answer 1

Answer:

21

Step-by-step explanation:

The Question Should be consecutive "odd" integers...

Let integers a, (a+2), (a+4)       [since they are consecutive odd]

Given: a+(a+2) = 4(a+4)-24

=>  2a+2 = 4a + 16 - 24

=>  2a+2 = 4a-8

=>  10 = 2a

=> a=5

a+2 =7

a+4=9

∴ a+ (a+2)+ (a+4) =5+7+9=21

[If numbers are consecutive, a=17/2, which is not an integer.]