Question

Find the sum of three consecutive numbers such that the sum of the first
Isecond is 15 more than the third.​

Answer 1

required three consecutive natural numbers are 16,17 and 18

Step-by-step explanation:

Let x,(x+1),(x+2) are three consecutive natural numbers.

According to the problem given,

The sum of the first and second is 15 more than the third number.

=> x+(x+1)-(x+2)=15

=> x+x+1-x-2=15

=> x-1=15

=> x = 15+1

=> x = 16

Therefore,

Required three consecutive natural numbers are :

x = 16,

x+1 = 16+1 = 17,

x+2 = 16+2 = 18

Answer 2

Answer:

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Step-by-step explanation:

Let the first consecutive number = x,

Second consecutive number = x + 1

and Third consecutive number = x + 2

According to the condition,

x+x+1=15+x+2

⇒2x+1=17+x

⇒2x-x=17-1

⇒x=16

∴ The first natural number = x = 16

∴ Second natural number = x+1 = 16+1 = 17

∴ Third natural number = x +2 = 16 + 2=18

Hence, the three consecutive natural numbers are 16, 17 and 18.