Find the sum of three - digit natural number which are divisible by 4.
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The three digital number which is divisible by 4 is
100,104,108,996
first term=100
d=104−100=4
last term=996
Then,
n=a=(n−1)×4
996=100+(n−1)×4
996−100=(n−1)4
4
896
=(n−1)
224=(n−1)
∴n=225
225 three digits number which is divisible by 4
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