Find the sum of three digit natural numbers divisuble by 11
Answers
Answer:
396
Step-by-step explanation:
121 (11x11)
132(11x12)
143(11x13)
→ 121+132+143=396
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Secondary SchoolMath 8 points
Find the sum of all 3 digit numbers divisible by 11?
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Atulpatidar123456789 Helping Hand
Answer:
Step-by-step explanation:
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mindfulmaisel Ambitious
The sum of all 3 digits divisible by 11 is 44,550.
As we know that, the below numbers which are being divisible by 11, such that
110, 121, 132, 990
The above series looks like the number are in A.P
To find ‘the last term of a series’ is = a + (n-1) d.
Where a = 110, d = 11.
Such that,
\begin{array}{l}{990=110+(n-1) 11} \\ {880=(n-1) 11} \\ {80=n-1} \\ {n=81}\end{array}
Sum of all the digits =\frac{n}{2}(2 a+(n-1) d)
\begin{aligned} &=\frac{81}{2}(2(110)+80(11)) \\ &=\frac{81}{2}(220+880) \\ &=\frac{81}{2}(1100) \\ &=81 \times 550 \\ &=44,550 \end{aligned}